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x^2+54x+9=0
a = 1; b = 54; c = +9;
Δ = b2-4ac
Δ = 542-4·1·9
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-24\sqrt{5}}{2*1}=\frac{-54-24\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+24\sqrt{5}}{2*1}=\frac{-54+24\sqrt{5}}{2} $
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